基于Python制作炸金花游戏的过程详解

　　# -*- coding: utf-8 -*-

　　import random

　　puke = [] # 存储扑克牌

　　num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']

　　hua_list = ['梅花', '红桃', '黑桃', '方块']

　　sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12,

　　'对子': 15, '顺子': 30, '顺金': 60, '豹子': 100}

　　count_new_list = [] # 存储玩家分数和排序后排名

　　count_dic = {} # 存储玩家分数

　　# 准备52张扑克

　　for hua in hua_list:

　　for num in num_list:

　　a = hua + num

　　puke.append(a)

　　player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []}

　　# 随机给五个玩家发牌

　　# print(len(puke))

　　for key, value in player_dic.items():

　　for i in range(3):

　　plate = random.sample(puke, 3)

　　player_dic[key] = plate

　　for i in plate:

　　puke.remove(i)

　　print(player_dic)

　　# 获取玩家的牌型

　　def paixing(list1):

　　num = []

　　huase = []

　　for i in list1:

　　a = i[2:]

　　b = i[:2]

　　num.append(a)

　　huase.append(b)

　　return num, huase

　　# sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4}

　　# 对数字的牌型进行排序

　　def sort(num):

　　new_num = []

　　sort_list2 = []

　　list1 = []

　　for i in num:

　　new_num.append(sort_dic[i])

　　new_num = sorted(new_num) # 排序后是[2, 4, 7]

　　for new in new_num:

　　sort_list2.append([k for k, v in sort_dic.items() if v == new])

　　for m in sort_list2:

　　for n in m:

　　list1.append(n)

　　return list1

　　# 对玩家的牌形统计分数

　　def count(num, huase):

　　a = 0

　　base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]]

　　if num[0] == num[1] and num[1] == num[2]:

　　paixing = '豹子'

　　a = base_count + sort_dic[paixing]

　　elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[

　　1] and huase[1] == huase[2]):

　　paixing = '顺金'

　　a = base_count + sort_dic[paixing]

　　elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (

　　huase[0] != huase[

　　1] or huase[1] != huase[2]):

　　paixing = '顺子'

　　a = base_count + sort_dic[paixing]

　　elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (

　　num[0] == num[2] and num[1] != num[0]):

　　paixing = '对子'

　　a = base_count + sort_dic[paixing]

　　else:

　　a = base_count

　　return a

　　# 对存储玩家分数的字典进行排序

　　def compare(count_dic):

　　d = list(zip(count_dic.values(), count_dic.keys()))

　　return sorted(d, reverse=True)

　　for key, value in player_dic.items():

　　num, huase = paixing(value)

　　num = sort(num)

　　count1 = count(num, huase)

　　count_dic[key] = count1

　　print(key + "的牌为：" + str(value))

　　count_new_list = compare(count_dic)

　　# print(count_new_list)

　　print('最终排名：' + " " + count_new_list[0][1] + "第一名" + " " + count_new_list[1][1] + "第二名" + " " + count_new_list[2][

　　1] + "第三名" + " " + count_new_list[3][1] + "第四名" + " " + count_new_list[4][1] + "第五名")